If c(x) = 4x – 2 and d(x) = x2 + 5x, what is (c*d)(x)?
c(x)=4x-2 and d(x)=\(x^{2} +5x\)
(c*d)(x)
(4x-2)(\(x^{2} +5x)\)
Open the brackets and multiply the terms in the order shown below;
4x(\(x^{2} +5x)\)-2(\(x^{2} +5x)\)
=4\(x^{3} +20 x^{2} -2 x^{2} -10x\)
=4\(x^{3} +18 x^{2} -10x\)
The value of (cd)(x) is 4x³ + 18x² - 10x
Given that,
∴ (cd)(x) = c(x)d(x) = (4x – 2)(\(x^{2} +5x\))
∴ (4x – 2)(\(x^{2} +5x\))
= (4x)(\(x^{2} +5x\)) -2(\(x^{2} +5x\))
= 4x³ + 20x² - 2x² - 10x
= 4x³ + 18x² - 10x
∴ The value of (cd)(x) is 4x³ + 18x² - 10x
Learn more about algebric multiplications here: https://brainly.com/question/2241589
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