Answer:
384.0 grams is the mass of a sample of gold that displaces 20.0 \(cm^3\) of water.
Explanation:
Density of gold = \(d=19.2 g/cm^3\)
Volume of water displaced gold = \(20.0 cm^3\)
Volume of water displaced is equal to the volume occupied by the gold sample.
Volume of the gold , v = \(20.0 cm^3\)
\(Density =\frac{Mass}{Volume}\)
Mass of gold :
\(Density\time Volume =19.2 g/cm^3\times 20.0 cm^3= 384.0 g\)
Mass of gold = 384.0 g
