Answer:
\(f(-a)=-a^2+1\)
Step-by-step explanation:
We have been a function \(f(x)=-(x^2-1)\). We are asked to simplify our function at the indicated value \(f(-a)\).
To find \(f(-a)\) for our given function, we will substitute \(x=-a\) in our given function as:
\(f(-a)=-((-a)^2-1)\)
We know that a negative number raised to an even power results in positive, so our function would be:
\(f(-a)=-(a^2-1)\)
Using distributive property \(a(b+c)=ab+ac\), we will get:
\(f(-a)=-1*a^2-1*-1\)
\(f(-a)=-a^2+1\)
Therefore, the value of \(f(-a)\) is \(-a^2+1\).
