find the sum of the arithmetic sequence. -10, -7, -4, -1, 2, 5, 8 select one: a. 11 b. -70 c. 0 d. -7
This is an aritmetic series;
a=-10
d=-7--10
d=3
n= 7
Sum=\(\frac{n}{2}\)(2a+(n-1)d)
Sum=\(\frac{7}{2} (2*(-10)+(7-1)3)\)
sum=3.5(-20+18)
sum=3.5(-2)
sum=-7
Answer:
d -7
Step-by-step explanation:
The sum of an arithmetic sequence Sn whose first and last terms are known may be expressed as
Sn = n/2(a + l)
where a and l are the first and last terms of the arithmetic sequence with n number of terms
Thus for the given sequence, the sum Sn is
S₇ = 7/2 (-10 + 8)
Since there are 7 terms in the sequence
= 3.5 * -2
= -7