what is the solution to the system of equations? y = 2x – 3.5 x – 2y = –14 (–7, 3.5) (3.5, –7) (7, 10.5) (10.5, 7)
y=2x-3.5
x-2y=-14
Solving by substitution by x in equation II the subject of the formula;
x=2y-14
Replacing in the first equation;
y=2(2y-14)-3.5
y=4y-28-3.5
y=4y-31.5
y-4y=-31.5
-3y=-31.5
y=\(\frac{-31.5}{-3}\)
y=10.5
we have the system of equations
\(y=2x-3.5\) --------> equation \(1\)
\(x-2y=-14\) --------> equation \(2\)
Multiply by \(2\) equation \(1\)
\(2y=4x-7\) --------> equation \(3\)
Adds equation \(2\) and equation \(3\)
\(x-2y=-14 \\ 2y=4x-7\\ --------\\ x=-14+4x-7\\ 4x-x=14+7\\ 3x=21\\ x=7\)
Find the value of y
\(y=2x-3.5\)
\(y=2*7-3.5\)
\(y=10.5\)
the solution of the system is the point \((7,10.5)\)
therefore
the answer is
\((7,10.5)\)