Molar mass :
\(H_2SO_4= 1*2+32+16*4= 98g/mol\)
Number of moles:
\(n = \frac{solute}{molar( mass)}\)
\(n = \frac{73.5g}{98g/mol}\)
\(n=0.75 (moles)\)
Volume = 3.0 L
\(M = \frac{n}{V}\)
\(M = \frac{0.75(moles)}{3.0L}\)
\(M = 0.25 mol/L ^{-1}\)
hope this helps!
