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In a quadrilateral, a student can draw two diagonals. In a pentagon, a student can draw five diagonals. In a hexagon, a student can draw nine different diagonals. How many diagonals can be drawn in a regular polygon that has 17 sides?

Verified Answer :

caylus

Hello,

Let's assume a polygonal of n vertices.

Starting from of vertice we can reach n-1 vertices by 2 must be excluded.

So there are n(n-1-2) possibilities but each  possibility is counted twice

Number of diagonals = n(n-3)/2

Examples:
n=4==>#=4(4-3)/2=41/2=2
n=5==>#=5(5-3)/2=52/2=5
n=6==>#=6(6-3)/2=63/2=9

n=17==>#=17*(17-3)/2=119.

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