what is the square root of –16?–8i–4i4i8i
The answer to your question is 4i.
we know that
\(i^{2} =-1\)
we have
\(\sqrt{-16} =\sqrt{(-1)*(16)} =\sqrt{(-1)*(4^{2})}\)
substitute the value of \(i^{2}=-1\) in the expression above
\(\sqrt{(-1)*(4^{2})}=\sqrt{i^{2}*4^{2}} \\ \\= 4i\)
therefore
the answer is
\(4i\)
