\(2(2x-4)=4+2x\\\\2\times2x-2\times4=4+2x\\\\4x-8=4+2x\ \ \ \ \ |add\ 8\ to\ both\ sides\ (on\ left\ side\ is\ -8)\\\\4x=12+2x\ \ \ \ \ \ |subtract\ 2x\ from\ both\ sides\ (on\ right\ side\ is\ +2x)\\\\2x=12\ \ \ \ |divide\ both\ sides\ by\ 2\\(we\ want\ the\ "x",\ therefore\ we\ get\ rid\ of\ the\ number\ 2)\\\\\boxed{\boxed{x=6}}\leftarrow Solution\)
