Answer:
\(x^{3} +3x^{2} -6x-18\)
Step-by-step explanation:
We are given zeroes and we need to find a cubic function with these zeroes
zeroes given are : \(\sqrt{6} , - \sqrt{6} , -3\)
Since these are zeroes so these can be written as:
[tex](x-\sqrt{6} )(x-(-\sqrt{6} ))(x-(-3)) = 0[/tex]
⇒\((x-\sqrt{6} )(x+\sqrt{6} )(x+3) = 0\)
⇒\((x^{2} +\sqrt{6} x- \sqrt{6} x -6)(x+3)\)
⇒\((x^{2} -6)(x+3)\)
⇒\(x^{3} +3x^{2} -6x-18\)
Thus the required cubic function is \(x^{3} +3x^{2} -6x-18\)
