solve 6/x -4 = 4/x for x and determine if the solution is extraneous or not. x = −8, extraneous x = −8, non-extraneous x = 8, extraneous x = 8, non-extraneous
\(\frac{6}{x-4} = \frac{4}{x} \\ 6x=4(x-4)=4x-16 \\ 2x=-16 \\ x=-8\)
To check: 6/(-8-4) = 4/-8
6/-12 = 4/-8
1/-2 = 1/-2
Therefore, x = −8, non-extraneous
Answer:
Option 2nd is correct that is x= -8 and non-extraneous.
Step-by-step explanation:
We have been given a function:
\(\frac{6}{x-4}=\frac{4}{x}\)
We need to solve the expression for x
Firstly, we will cross multiply we get:
\(6x=4(x-4)\)
\(\Rightarrow6x=4x-16\)
\(\Rightarrow 2x=-16\)
\(\Rightarrow x=-8\)
Extraneous is the point where the function becomes not defined.
Hence, when we substitute x=-8 in the given function
Function remains defined hence, x=-8 is non-extraneous
Therefore, Option 2nd is correct that is x= -8 and non-extraneous.