Answer:
Function which has real zeros at x = 3 and x = 7 is:
f(x)= x²-10x+21
Step-by-step explanation:
function has real zeros at x = 3 and x = 7
⇒ (x-3)(x-7)=0
⇒ x(x-7)-3(x-7)=0
⇒ x²-7x-3x+21=0
⇒ x²-10x+21=0
f(x)= x²-10x+21 has real zeros at x=3 and x=7
Hence, function which has real zeros at x = 3 and x = 7 is:
f(x)= x²-10x+21
