the work of a student to solve a set of equations is shown: equation a: y = 15 − 2z equation b: 2y = 3 − 4z step 1: −2(y) = −2(15 − 2z) [equation a is multiplied by −2.] 2y = 3 − 4z [equation b] step 2: −2y = 15 − 2z [equation a in step 1 is simplified.] 2y = 3 − 4z [equation b] step 3: 0 = 18 − 6z [equations in step 2 are added.] step 4: 6z = 18 step 5: z = 3 in which step did the student first make an error? step1 step 2 step 3 step 4

Verified Answer :

Neuron

If
you would like to solve a set of equations, you can do this using the following
steps:


equation
a: y = 15 - 2z       /(-2)

equation
b: 2y = 3 - 4z

__________________
-2y =
(-2)
(15 - 2z)


-2y = -30

  • 4z

2y = 3 -
4z

The
mistake was made at the step 2: −2y
= 15 − 2z [equation a in step 1 is simplified.]. The correct simplification
would be 
-2y = -30 + 4z.