Answer : Resistance of a clock is \(30\ \Omega\).
Explanation :
It is given that :
The current flowing in the clock, I = 0.3 A
Potential difference, V = 9 V
According to Ohm's law :
\(V=I\times R\)
So,
\(R=\dfrac{V}{I}\)
\(R=\dfrac{9\ V}{0.3\ A}\)
\(R=30\ \Omega\)
\(\Omega\) is the SI unit of the resistance given by a physicist Georg Simon Ohm.
So, the correct option is (d) i.e. \(30\ \Omega\)
Hence, this is the required solution.
