Answer:
The vertices of coordinates of image are Q'(0,-4), P'(-7,-6) and R'(-1,-2).
Step-by-step explanation:
The vertices of triangle QPR are Q(–4,0), P(–6, 7), and R(–2, 1). It is rotated 90° counterclockwise about the origin to form a new triangle Q'P'R'.
If a figure rotated 90° counterclockwise about the origin, then
\((x,y)\rightarrow (-y,x)\)
The coordinated of image are
\(Q(-4,0)\rightarrow Q'(0,-4)\)
\(P(-6,7)\rightarrow P'(-7,-6)\)
\(R(-2,1)\rightarrow R'(-1,-2)\)
Therefore the vertices of coordinates of image are Q'(0,-4), P'(-7,-6) and R'(-1,-2).
