\(\frac{x+6}{x+4} +\frac{x-3}{3}\)
make denomenators the same
we have
x+4 and 3
times the fraction with x+4 in denomenator with the fraction 3/3
times the fraction with 3 in denomenator with the fraction x+4
we get
\(\frac{3x+18}{3x+12} +\frac{x^2+x-12}{3x+12}\)
since common denoms, can add them to get
\(\frac{3x+18+x^2+x-12}{3x+12}\)
\(\frac{x^2+4x+6}{3x+12}\)
that is simplified
