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asasajenkins1 asasajenkins1
  • 10-07-2016
  • Mathematics
Answered

The length of a rectangle is 9 ft longer than twice the width. If the perimeter is 108 ft, find the length and the width of the rectangle

Verified Answer :

samgharsh1234
samgharsh1234 samgharsh1234
  • 10-07-2016

Let the width of rectangle be x ft
So length of rectangle be (2x+ 9 ) ft
Given
Perimeter of rectangle =2 (l+b)
Or
108= 2 (2x+9+x)
Or 108÷2=3x+9
Or 54=3x+9
Or 54-9=3x
Or 45=3x
Or x= 15
Required length = (2x+9)=(2×15+9)=39 ft
And width =x= 15 ft

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