The coordinates for the midpoint of \(ab\) are \((-1,\frac{13}{2})\).
You can use the midpoint formula (shown below) to solve this problem, by plugging in your two coordinates as \((x_{_1},y_{_1})\) and \((x_{_2},y_{_2}).\)
\(M = (\frac{x_{_1}+{x_{_2}} }{2} , \frac{y_{_1}+{y_{_2}} }{2})\)
Worked out, that would be:
\(M = (\frac{4+(-6) }{2} , \frac{7+6}{2}) \\ \\
= (\frac{4-6 }{2} , \frac{7+6}{2}) \\ \\
= (\frac{-2 }{2} , \frac{13}{2}) \\ \\
= (-1,\frac{13}{2})\)
