Determine the mass of 30.5 moles of diatomic oxygen (O2)
Molar mass O₂ = 16 x 2 = 32.0 g/mol
1 mol O₂--------------------------- 32.0 g
30.5 moles O₂-------------------- ? ( mass O₂)
mass O₂ = ( 30.5 ) x 32.0 / 1
mass O₂ = 976.0 / 1
= 976.0 grams of O₂
hope this helps!
Answer:
976g of \(O_{2}\)
Explanation:
First you should find the molar mass of the \(O_{2}\):
Molar mass of \(O_{2}\) = 2 molar mass of O
Molar mass of \(O_{2}\) = 2 16\(\frac{g}{mol}\)
Molar mass of \(O_{2}\) = 32\(\frac{g}{mol}\)
Then you should use the conversion factor:
\(30.5molesO_{2}*\frac{32gO_{2}}{1molO_{2}}=976gO_{2}\)
That is in 30.5 moles of \(O_{2}\) there are 976g of \(O_{2}\)