You can divide \(9\) by \(\frac{3}{5}\) to find the amount of pins, (let's call this number \(x\)), you can make with \(9 $ ft$\) of ribbon.
\(x=9 \div \frac{3}{5} \\ \\ x= \frac{9}{1} \div \frac{3}{5} \\ \\ x= \frac{9}{1} \times \frac{5}{3} \\ \\ x= \frac{9 \times 5}{1 \times 3} \\ \\ x= \frac{45}{3} \\ \\ x=15\)
So, \(15\) pins can be made.
