F(x)= sqrt x-5Find f-1
The answer is the first option, \(f\textsuperscript{-1}(x)=x^2+5; y \geq 5.\)When finding the inverse of a function, first replace \(f(x)\) with \(y\), and interchange the variables.\(f(x)= \sqrt{x-5} \\ y= \sqrt{x-5} \\ x= \sqrt{y-5}\)Then, solve the equation for y. This will give you the inverse function.\(x= \sqrt{y-5} \\ x^2 = y-5 \\ y = x^2+5 \\ f\textsuperscript{-1}(x)=x^2+5\)