Answer:
(C) and (D)
Step-by-step explanation:
The given equation of the circle is:
\((x-2)^2+(y+3)^2=4\)
A. Substitute the value of x=2 and y=-4 in the given equation, we have
\((2-2)^2+(-4+3)^2=4\)
\(1=4\)
which is not possible, thus (2,-4) does not lie in the given equation.
B. Substitute the value of x=2 and y=0 in the given equation, we have
\((2-2)^2+(0+3)^2=4\)
\(9=4\)
which is not possible, thus (2,0) does not lie in the given equation.
C.Substitute the value of x=0 and y=-3 in the given equation, we have
\((0-2)^2+(-3+3)^2=4\)
\(4=4\)
which is possible, thus (0.-3) lies in the given equation.
D.Substitute the value of x=2 and y=-5 in the given equation, we have
\((2-2)^2+(-5+3)^2=4\)
\(4=4\)
which is possible, thus (2,-5) lies in the given equation.
