Verified Answer :

konrad509

\((e^{-x})'=e^{-x}\cdot(-x)'=e^{-x}\cdot(-1)=-e^{-x}\)

olemakpadu

y = \(e^{-x}\)                

let u = x

y = \(e^{u}\)

dy/dx = dy/du   du/dx

dy/du =  \(e^{u}\)

du/dx = -1

dy/dx =  \(e^{u}\)  -1

dy/dx =  -\(e^{u}\)

dy/dx = -\(e^{-x}\)   

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