\(\sin 45=\dfrac{y}{11\sqrt6}\\
\dfrac{\sqrt2}{2}=\dfrac{y}{11\sqrt6}\\
2y=11\sqrt{12}\\
y=\dfrac{11\sqrt{12}}{2}\\\\
\tan 60=\dfrac{x}{y}\\
\tan 60=\dfrac{x}{\dfrac{11\sqrt{12}}{2}}\\
\sqrt3=\dfrac{2x}{11\sqrt{12}}\\
2x=11\sqrt{36}\\
2x=66\\
x=33 \Rightarrow D\)
