Verified Answer :

konrad509

\(\displaystyle \binom{3}{2}\cdot\binom{4}{4}\cdot \binom{5}{2}= \dfrac{3!}{2!1!}\cdot1\cdot\dfrac{5!}{2!3!}=3\cdot1\cdot10=30 \Rightarrow D\)

olemakpadu

In how many ways to choose: C = Combination

2 CDs from 3 CDs       =  ³C₂  =  (32)/(21) = 3

4 Cassettes from 4       =  ⁴C₄ = (4321)/(4321) = 1

2 DVDs from 5              =   ⁵C₂ = (54)/(21) = 10

Total = 3 1 10 = 30

Related Questions