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What is the temperature of 0.80 mol of a gas stored in a 275 mL cylinder at 175 kPa?

Use mc026-1.jpg and mc026-2.jpg.

4.6 K

7.2 K

61 K

96 K

Verified Answer :

olemakpadu

Using R as 8.314 J / mol. K.

P = 175kPa, = 175 000Pa = 175 000 N/m²,  V = 275mL = 275 cm³ = 275 10⁻⁶ m³,  n = 0.80 mole,  T = ?

By ideal gas equation:

PV = nRT

175000  275 10⁻⁶  = 0.8 8.314 T

T =    (175000  275 10⁻⁶) / (0.8 8.314 )

T = 7. 2355

T ≈ 7.2 K

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The temperature should be 7.2K

Given information:

There is 0.80 mol of a gas stored in a 275 mL cylinder at 175 kPa

Calculation of temperature:

175000 275 10⁻⁶  = 0.8 8.314 T

T =    (175000 275 10⁻⁶) / (0.8 * 8.314 )

T = 7. 2355

T ≈ 7.2 K

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