Answer:
\(\frac{f(x)}{g(x)}=-2x^2+7x-5\)
Step-by-step explanation:
\(f(x)=-2x^3 + x^2 + 16x -15\)
\(g(x)= x+3\)
Now we need to find f(x) divide by g(x)
\(\frac{f(x)}{g(x)}\)
Plug in f(x) and g(x)
\(\frac{f(x)}{g(x)}=\frac{-2x^3 + x^2 + 16x -15}{x+3}\)
LEts divide it using long division
-2x^2+7x-5
-----------------------------------------
\(x+3\) \(-2x^3 + x^2 + 16x -15\)
\(-2x^3-6x^2\)
------------------------------------------------(subtract)
\(7x^2+16x\)
\(7x^2+21x\)
---------------------------------------------------(subtract)
\(-5x - 15x\)
\(-5x - 15x\)
-------------------------------------------(subtract)
0
\(\frac{f(x)}{g(x)}=-2x^2+7x-5\)
