Answer:
The value of P(A|B) is \(\frac{15}{16}\).
Step-by-step explanation:
Given information: \(P(A\cap B)=\frac{3}{4}\), \(P(B)=\frac{4}{5}\)
Conditional probability
\(P(A|B)=\frac{P(A\cap B)}{P(B)}\)
\(P(A|B)=\frac{\frac{3}{4}}{\frac{4}{5}}\)
\(P(A|B)=\frac{3}{4}\times \frac{5}{4}\)
\(P(A|B)=\frac{15}{16}\)
Therefore the value of P(A|B) is \(\frac{15}{16}\).
