Consider the given quadratic equation \(50-x^2=0\)
\(x^2-50=0\)
Comparing the given quadratic equation to the general equation \(ax^2+bx+c=0\), we get a= 1, b=0 and c= -50
So, the solution to the quadratic equation is given by:
\(x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\)
\(x = \frac{-0 \pm \sqrt{0^2-4(1)(-50)}}{2}\)
\(x = \frac{\pm \sqrt{200}}{2}\)
\(x = \pm \sqrt2 (5)\)
\(x = \pm 5\sqrt2\)
So, the solutions to the given quadratic equation are \(x = \pm 5\sqrt2\).
