Answer:
\(h(x) = 2x^2+14x - 60\)
Step-by-step explanation:
\(h(3) = h(–10) = 0\)
h(3) means x=3
h(-10) means x=-10
Plug in x values and find out h(3) and h(-10)
LEts check with each option
\(h(x) = x^2 - 13x - 30\)
\(h(3) = 3^2 - 13(3) - 30=-60\) h(3) is not equal to 0
LEts check with option B
\(h(x) = x^2 - 7x - 30\)
\(h(3) = 3^2 - 7(3) - 30=0\) h(3) is not equal to 0
option C
\(h(x) = 2x^2 +26x - 60\)
\(h(3) = 2(3)^2+26(3)-60=36\) h(3) is not equal to 0
option D
\(h(x) = 2x^2+14x - 60\)
\(h(3) = 2(3)^2+14(3)-60=0\) h(3) is equal to 0
Plug in -10 for x
\(h(3) = 2(-10)^2+14(-10)-60=0\) h(-10) is equal to 0
