identify the oblique asymptote of f(x) = quantity x squared minus 4 x plus 8 over quantity x plus 2. y = 0 y = x - 2 y = x - 6 no oblique asymptote
Using long division, f(x) = x - 6 remainder 20
Therefore, oblique asymptote is y = x - 6
Answer:
Oblique asymptote is y= x- 6
Step-by-step explanation:
f(x)= \(\frac{x^2-4x+8}{x+2}\)
To find out ablique asymptote we use long division
x - 6
------------------------------
x+2 x^2- 4x+ 8
x^2+ 2x
------------------------------ (Subtract it )
- 6x + 8
- 6x - 12
------------------------------(Subtract it)
-20
Quotient is the oblique asymptote
Oblique asymptote is y= x- 6