Verified Answer :

nobillionaireNobley

\(\frac{4 m^{3} }{3 m^{2}n } \times \frac{9 n^{2} }{30 m^{2} n^{2} } \\ = \frac{36}{90} \times \frac{m^{3 }}{m^{4}} \times \frac{n^{2}}{n^{3}} \\ = \frac{2}{5mn}\)

Answer: Our simplified form will be

\(\frac{2}{5mn}\)

Step-by-step explanation:

Since we have given that

4 m cubed over 3 m squared n times 9 n squared over 30 m squared n squared.

\(\frac{4m^3}{3m^2n}\times \frac{9n^2}{30m^2n^2}\\\\\text{we will use }a^m\times b^n=a^{m+n}\\\\=\frac{4m}{3n}\times \frac{3}{10m^2}\\\\=\frac{2}{5mn}\)

Hence, our simplified form will be

\(\frac{2}{5mn}\)

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