How could Brent use a rectangle to model the factors of x2 – 7x + 6?

AHe could draw a diagram of a rectangle with dimensions x – 3 and x – 4 and then show the area is equivalent to the sum of x2, –3x, –4x, and half of 12.

BHe could draw a diagram of a rectangle with dimensions x + 7 and x – 1 and then show the area is equivalent to the sum of x2, 7x, –x, and 6.


CHe could draw a diagram of a rectangle with dimensions x – 1 and x – 6 and then show the area is equivalent to the sum of x2, –x, –6x, and 6.

DHe could draw a diagram of a rectangle with dimensions x – 4 and x + 3 and then show the area is equivalent to the sum of x2, –4x, 3x, and half of –12

Verified Answer :

Answer:

C

Step-by-step explanation:

He could draw a diagram of a rectangle with dimensions x – 1 and x – 6 and then show the area is equivalent to the sum of x^2, –x, –6x, and 6.

The expression is given as:

\(x^2 - 7x + 6\)


Expand

\(x^2 - 6x - x + 6\)

Factorize

\(x(x - 6) -1(x - 6)\)

Factor out x - 6

\((x - 1)(x - 6)\)

This means that the factors of \(x^2 - 7x + 6\) are x - 1 and x - 6

Hence, the true statement is (c)

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