\(-6g + 3g + 12 \ \textgreater \ -18\)
Start by combining like terms on both sides
-6+3=-3
Now we have:
\(-3g+ 12 \ \textgreater \ -18\)
To isolate g we need to subtract 12 from both sides -18-12= -30
Now we have
\(-3g \ \textgreater \ -30\)
Divide both sides by -3 to isolate g, now we have:
\(g\ \textgreater \ -10\)
When we divide an inequality by a negative we flip the sign so:
\(g\ \textgreater \ -10\)
becomes:
\(g\ \textless \ 10\)
Final answer:
\(g\ \textless \ 10\)
