Answer:
Option A is correct
\(f(x)=3x^2+1\)
Step-by-step explanation:
Use:
\((f+g)(x) = f(x)+g(x)\)
Given that:
\((f+g)(x)=3x^2+2x-1\) and g(x) = 2x-2
then;
\((f+g)(x) = f(x)+g(x)\)
Substitute the given values we have;
\(3x^2+2x-1 = f(x)+2x-2\)
Subtract 2x-2 from both sides we get;
\(3x^2+2x-1 -2x+2= f(x)\)
Combine like terms;
\(f(x) = 3x^2+1\)
Therefore, the function f(x) is, \(3x^2+1\)
