help!??!? How many different ways can a family of four sit at a rectangular dinner table with one person at each side?


A4 ways
B12 ways
C16 ways
D24 ways

Verified Answer :

The answer for these probability questions is always How many people Times(x) How sides does the shape have
So the Answer to this question would be 16 (4x4)
It works in different ways
e.g 
A combo of 5 different shirts and 3 different pants
How Many outfits could be made
(5x3) = 15

Use the fundamental principle of counting. In the first seat, we can choose the seater from the four persons. On the next seat, only 3 people would be available. On the second, there are 2 and finally 1 to the last seat. Multiply all the possible number of seaters,
                                4 x 3 x 2 x 1 = 16
Thus, the answer is letter C.