Answer :
The name of compound \(KI\) is, potassium iodide.
The name of compound \(Fe_2O_3\) is, iron (III) oxide.
The name of compound \((NH_4)_3PO_4\) is, ammonium phosphate.
Explanation :
Ionic compound : It is a type of compound that is made up of the ions of the two different elements in which one element is a metal and another element is a non-metal.
The rules of ionic compounds is given by:
- Positive ion is written first.
- The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
- In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.
(1) The given compound \(KI\) is an ionic compound. It is made up of two different ions which are potassium ion \((K^+)\) and iodide ion \((I^-)\).
So, the name of \(KI\) is, potassium iodide.
(2) The given compound \(Fe_2O_3\) is an ionic compound. It is made up of two different ions which are iron ion \((Fe^{3+})\) and oxide ion \((O^{2-})\). In this an oxidation state of iron is (+3).
So, the name of \(Fe_2O_3\) is, iron (III) oxide.
(3) The given compound \((NH_4)_3PO_4\) is an ionic compound. It is made up of two different ions which are ammonium ion \((NH_4^+)\) and phosphate ion \((PO_4^{3-})\).
So, the name of \((NH_4)_3PO_4\) is, ammonium phosphate.