Answer : The amount energy needed is, 0.9 cal
Solution :
Formula used :
\(Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})\)
where,
Q = heat required = ?
m = mass of copper = 10 g
c = specific heat of copper = \(0.09cal/g^oC\)
\(\Delta T=\text{Change in temperature}\)
\(T_{final}\) = final temperature = \(21^oC\)
\(T_{initial}\) = initial temperature = \(20^oC\)
Now put all the given values in the above formula, we get :
\(Q=10g\times 0.09cal/g^oC\times (21-20)^oC\)
\(Q=0.9cal\)
Therefore, the amount energy needed is, 0.9 cal
