What is the point-slope form of a line with slope -5 that contains the point (2, -1)?
Point slope formula:
\(y-y_1=m(x-x_1)\)
We know that:
y1=-1
x1=2
m=-5
So we plug those into the formula
\(y-(-1)=-5(x-2)\)
negative + negative= positive so..
Final answer:
\(y+1=-5(x-2)\)
point slope form
y-y1=m(x-x1) where
m=slope and you are given a point (x1,y1)
slope=-5
point is (2,-1)
x1=2
y1=-1
m=-5
so
y-(-1)=-5(x-2)
y+1=-5(x-2) is answer