What is the pH of a 1 ´ 10-5 M KOH solution?
KOH -------------> K⁺ + OH⁻pOH = - log [ OH⁻ ]pOH = - log [ 1 x 10⁻⁵ ]pOH = 5pH + pOH = 14pH + 5 = 14pH = 14 - 5pH = 9hope this helps!