Ariel has a plastic Ice cream cone in her food play set. The ice cream cone is a half sphere sitting on top of the cone. What is the approximate volume of the toy Ice cream cone? Use 3.14 for pie

Ariel has a plastic Ice cream cone in her food play set. The ice cream cone is a half sphere sitting on top of the cone. What is the approximate volume of the t class=

Verified Answer :

Volume of a half sphere:
Vs = 1/2 · 4/3 r³ π = 1/2 · 4/3 . 6³  · 3.14 = 452.16 cm³
Volume of the cone:
Vc = 1/3 · r² π = 1/3  · 36 · 3.14 = 301.44 cm³
Volume of the toy: Vs + Vc = 452.16 + 301.44 = 753. 60 cm³

Answer:

\(753.6 cm^{3}\)

Step-by-step explanation:

Given : The ice cream cone is a half sphere(hemisphere) sitting on top of the cone.

To Find : volume of the toy Ice cream cone.

Solution :

Refer the figure

We can see that radius of cone = radius of half sphere(hemisphere) = 6cm

Height of cone = 8 cm

Volume of the toy Ice cream cone = VOLUME OF CONE + VOLUME OF HEMISPHERE .

First calculate the volume of cone .

Formula of volume of cone :  \(\frac{1}{3} \pi r^{2} h\)

Where r = radius of cone and h = height of cone and    \(\pi = 3.14\)

So, the volume of ice cream cone :

⇒\(\frac{1}{3} \pi r^{2} h\)


⇒\(\frac{1}{3} *3.14*(6)^{2} *8\)


⇒\(\frac{1}{3} *3.14*36*8\)


⇒\(\frac{904.32}{3}\)


⇒\(301.44\)

Thus the volume of cone is   \(301.44 cm^{3}\)

Now formula of volume of sphere :

\(\frac{2}{3} \pi r^{3}\)

r = radius = 6 cm

\(\frac{2}{3} *3.14*(6)^{3}\)

\(\frac{2}{3} *3.14*216\)

\(\frac{1356.48}{3}\)

\(452.16\)

Thus the volume of the hemisphere is     \(452.16cm^{3}\)

Now , Since we know that

Volume of the toy Ice cream cone = VOLUME OF CONE + VOLUME OF HEMISPHERE .

⇒ 301.44 +452.16

⇒  \(753.6 cm^{3}\)

Hence, The volume of the toy Ice cream cone is    \(753.6 cm^{3}\)