For an angle θ with the point (15, −8) on its terminating side, what is the value of cosine?
cos x = adyacent side / hypothenuse
adyacent side = x = 15
hypothenuse = √(x^2 + y^2) = √[(15)^2 + (-8)^2] = 17
cos x = 15/17 ≈ 0.88
Answer:
The value of cosθ is \(\frac{15}{17}\)
Step-by-step explanation:
It is given that an angle θ with the point (15, −8) on its terminating side.
Here x=adjacent side=15 units and y=opposite side =-8 units,
Using pythagoras theorem,
\(\text{hypotenuse}^2=\text{base}^2+\text{opposite side}^2\)
\(\text{hypotenuse}^2=(15)^2+(-8)^2\)
\(\text{hypotenuse}^2=225+64=289\)
\(\text{hypotenuse}^2=17\)
Cosine is defined as
\(\cos \theta=\frac{base}{hypotenuse}\)
\(\cos \theta=\frac{15}{17}\)
Therefore the value of cosθ is \(\frac{15}{17}\).