what is the value of the discriminant, b2 − 4ac, for the quadratic equation 0 = −2x2 − 3x 8, and what does it mean about the number of real solutions the equation has? the discriminant is −55, so the equation has 2 real solutions. the discriminant is −55, so the equation has no real solutions. the discriminant is 73, so the equation has 2 real solutions. the discriminant is 73, so the equation has no real solutions.
Rewrite the equation:
-2x^2 - 3x + 8 = 0
2x^2 + 3x -8 =0
Where a=2, b=3 and c=-8
Then b^2 - 4ac = 3^2 - 4(2)(-8) = 9 + 64 = 73
A positive discriminant implies that the equation has two different real solutions.
Answer: the discriminant is 73, so the equation has 2 real solution
Answer:
The correct option 3.
Step-by-step explanation:
The given equation is
\(-2x^2-3x+8=0\)
The discriminant formula is
\(D=b^2-4ac\)
The value of discriminant for the given quadratic equation is
\(D=(-3)^2-4(-2)(8)\)
\(D=9+64\)
\(D=73\)
Therefore the value of the discriminant is 73.
The number of real solution depends on the value of discriminant.
1. If D=0, then the quadratic equation has one real solution.
2. If D>0, then the quadratic equation has two real solutions.
3. If D<0, then the quadratic equation has not real solutions.
Since the value of discriminant is greater than 0, therefore the equation has two real solutions.
Option 3 is correct.