Verified Answer :

dalendrk

\((x^2)\left(2xy^3\right)^5=(x^2)\left(2^5x^5y^{3\cdot5}\right)=(x^2)(32x^5y^{15})\\\\=32x^{2+5}y^{15}=\boxed{32x^7y^{15}}\to\boxed{c.}\)

Answer:

c

Step-by-step explanation:

We can solve and simply the expression using the product rule for the following expression:

\(=x^2*(2*x*y^5)^5\)

If x is multiplied by a x we can add their exponents, if a bracket has an exponent we can multiply the exponent with the exponent of each term in the bracket.

\(=x^2*(2^5*x^5*y^15)\)

\(=32*x^7*y^15\)

Therefore the answer is c

Related Questions