shayna enlarged a square photo by adding 10 inches to each side so it could be seen on a large poster. the area of the enlarged photo is 256 square inches. in the equation (x 10)2 = 256, x represents the side measure of the original square photo. what were the dimensions of the original photo? 4 inches by 4 inches 6 inches by 6 inches 10 inches by 10 inches 12 inches by 12 inches
Hello,
Answer B 6*6 in²
(x+10)²=256
==>(x+10)²-16²=0
==>(x+10-16)(x+10+16)=0
==>x=6 or x=-26 (excluded)
Answer:
The original dimension was 6 inches by 6 inches.
Step-by-step explanation:
'x' represents the side measure of the original square photo.
Given is that Shayna enlarged a square photo by adding 10 inches to each side so it could be seen on a large poster.
The given equation is:
\((x+10)^{2} =256\)
Solving for 'x' as x was the original dimension in which 10 was added.
\(x^{2} +20x+100=256\)
\(x^{2} +20x-156=0\)
\(x^{2} +26x-6x-156=0\)
\(x(x+26)-6(x+26)=0\)
\((x+26)(x-6)=0\)
\(x=-26\) and \(x=6\)
Neglecting the negative value as dimension cannot be negative.
So, we have x=6 inch
Therefore, the original dimension was 6 inches by 6 inches.