Verified Answer :

dalendrk

\((3+4i)(5-2i)=(3)(5)-(3)(2i)+(4i)(5)-(4i)(2i)\\\\=15-6i+20i-8i^2=15+14i-8(-1)=15+14i+8\\=\boxed{23+14i}\)

Answer:

(3 + 4i) + (5 − 2i) = 8 + 2i

Step-by-step explanation:

Group the real part and the imaginary part of the complex number

\((a + bi) ± (c + di) = (a ± c) + (b ± d)I\) < disregard A, brainly is misreading the ± symbol.

(3 + 5) + (4 - 2)i

refine

8 + 2i

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