we know that
the point-slope form of the equation of the line is equal to
\(y-y1=m(x-x1)\)
so
Step \(1\)
Find the slope m
the slope is equal to
\(m=\frac{(y2-y1)}{(x2-x1)}\)
Let
\(A(-3,2)\\ B(2,1)\)
\(m=\frac{(1-2)}{(2+3)}\)
\(m=-\frac{1}{5}\)
Step \(2\)
with m and point A find the equation of the line
\(y-2=-\frac{1}{5}(x+3)\)
therefore
the answer is
the point-slope form of the equation is equal to
\(y-2=-\frac{1}{5}(x+3)\)
