Answer-
The width of the pieces of construction paper is \(6\dfrac{3}{4}\ \text{inch}\)
Solution-
James has a piece of construction paper with an area \(65\dfrac{1}{4}=\dfrac{261}{4}\) inch²
Length of the paper is \(9\dfrac{2}{3}=\dfrac{29}{3}\) inch
We know that,
\(\text{Area}=\text{Length}\times \text{Width}\)
Putting the values,
\(\Rightarrow \dfrac{261}{4}=\dfrac{29}{3}\times \text{Width}\)
\(\Rightarrow \text{Width}=\dfrac{261}{4}\times \dfrac{3}{29}\)
\(\Rightarrow \text{Width}=\dfrac{9\times 3}{4}\)
\(\Rightarrow \text{Width}=\dfrac{27}{4}\)
\(\Rightarrow \text{Width}=6\dfrac{3}{4}\ \text{inch}\)
Therefore, the width of the pieces of construction paper is \(6\dfrac{3}{4}\ \text{inch}\)
