To solve Lance’s equation, 2(x + 10) = 60, first
A.subtract 10 from both sides
B.multiply both sides by 2
C.divide both sides by 2
D.add 10 to both sides
Then
A.subtract 10 from both sides
B.add 10 to both sides
C.multiply both sides by 2
D.divide both sides by 2
Solve Lance's equation, 2(x + 10) = 60, for x. According to his model, the length of the rectangle is
A10 cm
B43 cm
C15 cm
D20 cm
To solve Olivia’s equation, 2x + 20 = 60, first
A.subtract 20 from both sides
B.multiply both sides by 2
C.divide both sides by 2
D.add 20 to both sides
Then
A.multiply both sides by 2
B.add 20 to both sides
C.subtract 20 from both sides
D.divide both sides by 2
Solve Olivia’s equation, 2x + 20 = 60, for x. According to her model, the length of the rectangle is
A30 cm
B2 cm
C20 cm
D15 cm
The two equations with different solution steps lead to
AThe same
BDifferent
answer(s), because 2(x + 10) = 60 and 2x + 20 = 60
AAre not
BAre
equivalent by the distributive property.
A.subtract 10 from both sides
B.multiply both sides by 2
C.divide both sides by 2
D.add 10 to both sides
Then
A.subtract 10 from both sides
B.add 10 to both sides
C.multiply both sides by 2
D.divide both sides by 2
Solve Lance's equation, 2(x + 10) = 60, for x. According to his model, the length of the rectangle is
A.subtract 20 from both sides
B.multiply both sides by 2
C.divide both sides by 2
D.add 20 to both sides
Then
A.multiply both sides by 2
B.add 20 to both sides
C.subtract 20 from both sides
D.divide both sides by 2
Solve Olivia’s equation, 2x + 20 = 60, for x. According to her model, the length of the rectangle is