solve: 25x2 − 36 = 0. x = 6, 5 x = −6, −5 x = 36 over 25, x = − 36 over 25 x = 6 over 5, x = − 6 over 5
\(25 x^{2} =36 \\ x^{2} = \frac{36}{25} \\ x= \pm \sqrt{ \frac{36}{25} } \\ x= \pm \frac{6}{5} \\ x= \frac{6}{5} \ or \ - \frac{6}{5}\)
Answer:
\(x=-\frac{6}{5}\text{ or }x=\frac{6}{5}\).
Step-by-step explanation:
We have been given an equation \(25x^2-36=0\). We are asked to solve our given equation.
First of all, we will add 36 on both sides of our equation.
\(25x^2-36+36=0+36\)
\(25x^2=36\)
Now, we will divide both sides of our equation by 25.
\(\frac{25x^2}{25}=\frac{36}{25}\)
\(x^2=\frac{36}{25}\)
Upon taking square root of both sides we will get,
\(x=\sqrt{\frac{36}{25}}\)
\(x=\sqrt{\frac{6^2}{5^2}}\)
\(x=\pm\frac{6}{5}\)
Therefore, the solution of our given equation are \(x=-\frac{6}{5}\text{ or }x=\frac{6}{5}\).